Locate the absolute extrema of the function $f ( x ) = - 4 x ^ { 2 } + 8 x - 2$ on the closed interval $[ - 2,2 ]$ .
A)no absolute max; absolute min: f(1)= 2
B)absolute max: f(-2)= -34 ; absolute min: f(1)= 2
C)absolute max: f(1)= 2 ; no absolute min
D)absolute max: f(1)= 2 ; absolute min: f(-2)= -34
E)no absolute max or min

Question

Quizplus · Accepted Answer

The function is a downward-opening parabola. The vertex at x=1 gives the maximum value f(1)=2, and the endpoint x=-2 gives the minimum value f(-2)=-34.

Locate the Absolute Extrema of the Function f(x)=−4x2+8x−2f ( x ) = - 4 x ^ { 2 } + 8 x - 2f(x)=−4x2+8x−2

Locate the Absolute Extrema of the Function $f ( x ) = - 4 x ^ { 2 } + 8 x - 2$