Find the limit. $\lim _ { x \rightarrow \infty } \frac { 7 x + 4 } { 8 x ^ { 2 } + 8 }$
A) $\infty$
B)1
C)0
D) $\frac { 7 } { 8 }$
E) $\frac { 1 } { 2 }$

Question

Quizplus · Accepted Answer

To find the limit of the given function as $x$ approaches infinity, divide every term by the highest power of $x$ in the denominator, which is $x^2$. This gives $\lim _ { x \rightarrow \infty } \frac { 7/x + 4/x^2 } { 8 + 8/x^2 }$. As $x$ approaches infinity, $7/x$ and $4/x^2$ approach 0, making the numerator approach 0, and the denominator approaches 8, making the whole fraction approach 0.

Find the Limit lim⁡x→∞7x+48x2+8\lim _ { x \rightarrow \infty } \frac { 7 x + 4 } { 8 x ^ { 2 } + 8 }limx→∞​8x2+87x+4​

Find the Limit $\lim _ { x \rightarrow \infty } \frac { 7 x + 4 } { 8 x ^ { 2 } + 8 }$