Analytically determine the location(s) of any horizontal asymptote(s). $f ( x ) = \frac { x - 80 } { x ^ { 2 } + 1100 }$
A) $y = 0$
B) $y = 0.072727$
C) $y = 33.166248$
D) $y = - 33.166248$
E)no horizontal asymptotes

Question

Quizplus · Accepted Answer

For the given function $f(x) = \frac{x - 80}{x^2 + 1100}$, the degree of the polynomial in the numerator is less than the degree of the polynomial in the denominator. This means that as $x$ approaches infinity, the value of $f(x)$ approaches 0. Therefore, the horizontal asymptote is $y = 0$.

Analytically Determine the Location(s) of Any Horizontal Asymptote(s) f(x)=x−80x2+1100f ( x ) = \frac { x - 80 } { x ^ { 2 } + 1100 }f(x)=x2+1100x−80​

Analytically Determine the Location(s) of Any Horizontal Asymptote(s) $f ( x ) = \frac { x - 80 } { x ^ { 2 } + 1100 }$