After t years, the remaining mass y(in grams) of 16 grams of a radioactive element whose half-life is 32 years is given by $y = 16 \left( \frac { 1 } { 2 } \right) ^ { t / 32 }$ , for $t \geq 0$ . How much of the initial mass remains after 96 years? Round your answer to two decimal places.
A)4.00 grams
B)3.20 grams
C)4.30 grams
D)4.90 grams
E)2.00 grams

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The Answer of After t years, the remaining mass y(in grams) of 16 grams of a radioactive element whose half-life is 32 years is given by $y = 16 \left( \frac { 1 } { 2 } \right) ^ { t / 32 }$ , for $t \geq 0$ . How much of the initial mass remains after 96 years? Round your answer to two decimal places.
A)4.00 grams
B)3.20 grams
C)4.30 grams
D)4.90 grams
E)2.00 grams

After T Years, the Remaining Mass Y(in Grams) of 16 y=16(12)t/32y = 16 \left( \frac { 1 } { 2 } \right) ^ { t / 32 }y=16(21​)t/32

After T Years, the Remaining Mass Y(in Grams) of 16 $y = 16 \left( \frac { 1 } { 2 } \right) ^ { t / 32 }$