Find the intercepts of the plane given by $3 x - 9 z = 18$ .
A)The $x$ -intercept is $( 0,0,6 )$ .The $z$ -intercept is $( - 2,0,0 )$ .
B)The $x$ -intercept is $( 0,6,0 )$ .The $z$ -intercept is $( - 2,0,0 )$ .
C)The $x$ -intercept is $( 0 , - 6,0 )$ .The $z$ -intercept is $( - 2,0,0 )$ .
D)The $x$ -intercept is $( - 6,0,0 )$ .The $z$ -intercept is $( 0,0 , - 2 )$ .
E)The $x$ -intercept is $( 6,0,0 )$ .The $z$ -intercept is $( 0,0 , - 2 )$ .

Question

Quizplus · Accepted Answer

To find the $x$-intercept, set $y = 0$ and $z = 0$ in the equation $3x - 9z = 18$, solving gives $x = 6$, so the $x$-intercept is $(6,0,0)$. For the $z$-intercept, set $x = 0$ and $y = 0$, solving $3x - 9z = 18$ for $z$ gives $z = -2$, so the $z$-intercept is $(0,0,-2)$.

Find the Intercepts of the Plane Given By 3x−9z=183 x - 9 z = 183x−9z=18

Find the Intercepts of the Plane Given By $3 x - 9 z = 18$