Find the indefinite integral of $\int \frac { \sec x \tan x } { \sec x - 2 } d x$ .
A) $\ln | \sec x + 2 | + C$
B) $\ln | \sec x - 2 | + C$
C) $\ln | 2 \cos x + \sec x | + C$
D) $\ln | \cos x - 2 | + C$
E) $\ln | \cos x + 2 | + C$

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The Answer of Find the indefinite integral of $\int \frac { \sec x \tan x } { \sec x - 2 } d x$ .
A) $\ln | \sec x + 2 | + C$
B) $\ln | \sec x - 2 | + C$
C) $\ln | 2 \cos x + \sec x | + C$
D) $\ln | \cos x - 2 | + C$
E) $\ln | \cos x + 2 | + C$

Find the Indefinite Integral Of ∫sec⁡xtan⁡xsec⁡x−2dx\int \frac { \sec x \tan x } { \sec x - 2 } d x∫secx−2secxtanx​dx

Find the Indefinite Integral Of $\int \frac { \sec x \tan x } { \sec x - 2 } d x$