Subtract: $\begin{array} { r }
14 \frac { 2 } { 9 } \
\
- \quad 8 \frac { 8 } { 11 } \
\hline
\end{array}$
A) $4 \frac { 49 } { 99 }$
B) $5 \frac { 49 } { 99 }$
C) $4 \frac { 98 } { 891 }$
D) $5 \frac { 98 } { 891 }$
E) $4 \frac { 49 } { 198 }$

Question

Subtract: $\begin{array} { r } 
14 \frac { 2 } { 9 } \
\
- \quad 8 \frac { 8 } { 11 } \
\hline
\end{array}$
A) $4 \frac { 49 } { 99 }$
B) $5 \frac { 49 } { 99 }$
C) $4 \frac { 98 } { 891 }$
D) $5 \frac { 98 } { 891 }$
E) $4 \frac { 49 } { 198 }$

Quizplus · Accepted Answer

To subtract the given fractions, first convert them to improper fractions: $14 \frac{2}{9} = \frac{128}{9}$ and $8 \frac{8}{11} = \frac{96}{11}$. To subtract, find a common denominator, which is $99$, and then subtract: $\frac{128}{9} - \frac{96}{11} = \frac{128*11 - 96*9}{99} = \frac{1408 - 864}{99} = \frac{544}{99}$, which simplifies to $5 \frac{49}{99}$.

Subtract 1429−8811\begin{array} { r } 14 \frac { 2 } { 9 } \\\\- \quad 8 \frac { 8 } { 11 } \\\hline\end{array}1492​−8118​​​

Subtract $\begin{array} { r } 14 \frac { 2 } { 9 } \\\\- \quad 8 \frac { 8 } { 11 } \\\hline\end{array}$