Consider the following code snippet.
Scanner inputFile = new Scanner("dataIn.txt");
Which of the following statements is correct?
A)This code will not open a file named "dataIn.txt", but will treat the string "dataIn.txt" as an input value.
B)This code will open a file named "dataIn.txt" for writing.
C)This code will create a new file named "dataIn.txt".
D)This code will open an existing file named "dataIn.txt" for reading.

Question

Quizplus · Accepted Answer

The provided code snippet initializes a Scanner object with a string literal, which means the Scanner will treat the string "dataIn.txt" as the actual data to be scanned, not as a file path. To open a file, a File object or similar would need to be passed to the Scanner.

Consider the Following Code Snippet