Which of the following options checks that character ch is neither a letter nor a white space?
A)if (!Character.isLetter(ch) || !Character.isWhiteSpace(ch))
B)if (!(Character.isLetter(ch) || Character.isWhiteSpace(ch)))
C)if (!(Character.isLetter(ch) && Character.isWhiteSpace(ch)))
D)if (!Character.isLetter(ch) || Character.isWhiteSpace(ch))

Question

Quizplus · Accepted Answer

The expression !(Character.isLetter(ch) || Character.isWhiteSpace(ch)) will evaluate to true if ch is neither a letter nor a whitespace. This is because the || (or) operator means that the expression is true if either operand is true. By negating the entire expression with the ! operator, we are checking for the case where both operands are false, which means ch is not a letter and not a whitespace. Option A and D are incorrect because the || operator would make the expression true even if one of the operands is false. Option C is incorrect because the && operator would require that both operands be true, which is not what we want.

Which of the Following Options Checks That Character Ch Is