Consider the following loop: int n=1; double x=0; double s; do { s=1.0 /(n * n) ; x=x+5 ; n++; } while (s0.01); System. out. println(x); Which loop below is an equivalent loop? A) double x=0; double s=1; for (int k=1 ; s0.01 ; k++ ) { s=1.0 /(k * k) ; x=x+s ; } System. out. println(x); B) double x=0; double s=1; for (int k=1 ; k0.01) { s=1.0 /(k * k) ; x=x+s ; k++; } System.out. println(x); D) double x=0; double s=10; int k=1; while (s0.01) { s=1.0 /(k * k) ; x=x+s; k++; } System.out. println(x);

Question

Consider the following loop: 
int n=1;
double x=0;
double s;
do
{
s=1.0 /(n * n) ;
x=x+5 ;
n++;
}
while (s>0.01);
System. out. println(x);
Which loop below is an equivalent loop?
A) double x=0;
double s=1;
for (int k=1 ; s>0.01 ; k++ )
{
s=1.0 /(k * k) ;
x=x+s ;
}
System. out. println(x);
B) double x=0;
double s=1;
for (int k=1 ; k<100 ; k++ )
{
s=1.0 /(k * k) ;
x=x+5;
}
System. out.println(x);
C) double x=0;
double s=1;
int k=10;
while (s>0.01)
{
s=1.0 /(k * k) ;
x=x+s ;
k++;
}
System.out. println(x);
D) double x=0;
double s=10;
int k=1;
while (s>0.01)
{
s=1.0 /(k * k) ;
x=x+s;
k++;
}
System.out. println(x);

Quizplus · Accepted Answer

The equivalent loop should have the same output as the original loop. In order to have the same output, the loop must calculate the sum of 1/n^2 until the sum is less than or equal to 0.01. Only option A fits these criteria, as it correctly calculates the sum of 1/n^2 in the loop and stops when the sum is less than or equal to 0.01. Option B calculates the sum of 5 for 100 iterations, which is not equivalent. Option C starts the loop at k=10 and does not stop when the sum is less than or equal to 0.01, which is not equivalent. Option D starts s at 10 and does not stop when the sum is less than or equal to 0.01, which is not equivalent.

Consider the Following Loop