A man pulls a sled horizontally by exerting $641 b$ on the rope that is tied to its front end. If the rope makes an angle of $45 ^ { \circ }$
With horizontal, find the work done in moving the sled $35$
Ft
A) $2929.17$
Ft-lb
B) $629.17$
Ft-lb
C) $1583.92$
Ft-lb
D) $630.25$
Ft-lb
E) $1829.17$
Ft-lb

Question

Quizplus · Accepted Answer

To calculate the work done in moving the sled, we need to use the formula:

Work = force x distance x cos(theta)

where force is the applied force, distance is the displacement of the sled, and theta is the angle between the force vector and the displacement vector.

In this case, the force exerted by the man is 641 lb, and the sled is being moved horizontally, so theta = 45 degrees. The distance the sled is moved is 35 ft.

Plugging these values into the formula, we get:

Work = 641 lb x 35 ft x cos(45)
Work = 641 lb x 35 ft x (1/sqrt(2))
Work = 1583.92 ft-lb

Therefore, the answer is C: 1583.92 ft-lb.

A Man Pulls a Sled Horizontally by Exerting 641b641 b641b On the Rope That Is Tied to Its Front End

A Man Pulls a Sled Horizontally by Exerting $641 b$ On the Rope That Is Tied to Its Front End