The system is linear. $\left\{ \begin{array} { r }
x + 2 y + z = 3 \
\sqrt { 2 } x + y - \sqrt { 3 } z = 1 \
x + y + 4 z = - 4
\end{array} \right.$

Name: The system is linear. $\left\{ \begin{array} { r } x + 2 y + z = 3 \\ \sqrt { 2 } x + y - \sqrt { 3 } z = 1 \\ x + y + 4 z = - 4 \end{array} \right.$
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Question

The system is linear. $\left\{ \begin{array} { r } 
x + 2 y + z = 3 \
\sqrt { 2 } x + y - \sqrt { 3 } z = 1 \
x + y + 4 z = - 4
\end{array} \right.$

Quizplus · Accepted Answer

The system consists of three equations with each term being either a constant or a linear term (first power) of the variables $x$, $y$, or $z$, which defines a linear system.

The System Is Linear {x+2y+z=32x+y−3z=1x+y+4z=−4\left\{ \begin{array} { r } x + 2 y + z = 3 \\\sqrt { 2 } x + y - \sqrt { 3 } z = 1 \\x + y + 4 z = - 4\end{array} \right.⎩⎨⎧​x+2y+z=32​x+y−3​z=1x+y+4z=−4​

The System Is Linear $\left\{ \begin{array} { r } x + 2 y + z = 3 \\\sqrt { 2 } x + y - \sqrt { 3 } z = 1 \\x + y + 4 z = - 4\end{array} \right.$