Solve the system. $\left\{ \begin{array} { l }
y = 3 - 2 x \
y - 4 = 2 x
\end{array} \right.$
A) $x = - 0.25 , y = 3.5$
B) $x = 3.5 , y = - 0.25$
C) $x = - 0.35 , y = 2.5$
D) $x = - 1.5 , y = 2.5$
E)none

Question

Solve the system. $\left\{ \begin{array} { l } 
y = 3 - 2 x \
y - 4 = 2 x
\end{array} \right.$
A) $x = - 0.25 , y = 3.5$
B) $x = 3.5 , y = - 0.25$
C) $x = - 0.35 , y = 2.5$
D) $x = - 1.5 , y = 2.5$
E)none

Quizplus · Accepted Answer

To solve the system, we can set the two equations equal to each other since they both equal y: $3 - 2x = 2x + 4$. Solving for x, we get $3 - 4 = 4x$, so $x = -0.25$. Substituting x back into one of the original equations, $y = 3 - 2(-0.25) = 3.5$.

Solve the System {y=3−2xy−4=2x\left\{ \begin{array} { l } y = 3 - 2 x \\y - 4 = 2 x\end{array} \right.{y=3−2xy−4=2x​

Solve the System $\left\{ \begin{array} { l } y = 3 - 2 x \\y - 4 = 2 x\end{array} \right.$