Find the domain of the function. $f ( x ) = 3 x - \frac { 2 } { \sqrt { x + 1 } }$
A) $( - 1,1 )$
B) $( - \infty , - 1 ) \cup ( 1 , \infty )$
C) $( - 1 , \infty )$
D) $( - \infty , - 1 ] \cup [ 1 , \infty )$
E)none of these

Question

Quizplus · Accepted Answer

The domain of $f(x) = 3x - \frac{2}{\sqrt{x+1}}$ is determined by the condition that the expression under the square root, $x + 1$, must be greater than 0 to avoid taking the square root of a negative number. This gives $x + 1 > 0$, which simplifies to $x > -1$. Therefore, the domain is all real numbers greater than -1, which is $(-1, \infty)$.

Find the Domain of the Function f(x)=3x−2x+1f ( x ) = 3 x - \frac { 2 } { \sqrt { x + 1 } }f(x)=3x−x+1​2​

Find the Domain of the Function $f ( x ) = 3 x - \frac { 2 } { \sqrt { x + 1 } }$