Find the domain of the function. $$f ( x ) = \frac { 1 } { x } + \frac { 1 } { x + 1 }$$
A) $( - \infty , 0 )$
B) $( - \infty , - 1 ) \cup ( - 1,0 ) \cup ( 0 , \infty )$
C) $( - \infty , - 1 ) \cup ( - 1,0 )$
D) $( - \infty , 0 ) \cup ( 0 , \infty )$
E) none of these

Question

Quizplus · Accepted Answer

The domain of a rational function is the set of all real numbers except those that make the denominator(s) equal to zero. For this function, we want to avoid values of $x$ that make $x$ or $x+1$ equal to zero. Therefore, the domain is all real numbers except $0$ and $-1$. This can be written as $(-\infty,-1)\cup(-1,0)\cup(0,\infty)$. Hence, the correct choice is $\boxed{	extbf{(B)}}$.

Find the Domain of the Function f(x)=1x+1x+1f ( x ) = \frac { 1 } { x } + \frac { 1 } { x + 1 }f(x)=x1​+x+11​

Find the Domain of the Function $f ( x ) = \frac { 1 } { x } + \frac { 1 } { x + 1 }$