Given $f ( x ) = 2 + x ^ { 2 }$ and $g ( x ) = \sqrt { x - 4 }$, find $( f \circ g ) ( 4 )$
A) $( f \circ g ) ( 4 ) = 2$
B) $( f \circ g ) ( 4 ) = 4$
C) $( f \circ g ) ( 4 ) = - 2$
D) $( f \circ g ) ( 4 ) = 0$
E) $( f \circ g ) ( 4 ) = 1$

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The Answer of Given $f ( x ) = 2 + x ^ { 2 }$ and $g ( x ) = \sqrt { x - 4 }$, find $( f \circ g ) ( 4 )$
A) $( f \circ g ) ( 4 ) = 2$
B) $( f \circ g ) ( 4 ) = 4$
C) $( f \circ g ) ( 4 ) = - 2$
D) $( f \circ g ) ( 4 ) = 0$
E) $( f \circ g ) ( 4 ) = 1$

Given f(x)=2+x2f ( x ) = 2 + x ^ { 2 }f(x)=2+x2

Given $f ( x ) = 2 + x ^ { 2 }$