A block of unknown metal has dimensions: $1 \mathrm {~cm} ^ { \times } 1 \mathrm {~cm} ^ { \times } 3 \mathrm {~cm}$ .The block's density is $80000 ~ { \mathrm { kg } } / \mathrm { m } ^ { 3 }$ .What is the mass of the block?
A)24g
B)240g
C)2.4kg
D)24kg

Question

Quizplus · Accepted Answer

The volume of the block is $1 \mathrm {~cm} ^ { \times } 1 \mathrm {~cm} ^ { \times } 3 \mathrm {~cm} = 3 \mathrm {~cm} ^ { 3 }$. The density of the block is $80000 ~ { \mathrm { kg } } / \mathrm { m } ^ { 3 }$. So, the mass of the block is $\rho V = 80000 \mathrm {~kg} / \mathrm { m } ^ { 3 } \times 3 \mathrm {~cm} ^ { 3 } = 240 \mathrm {~g}$.

A Block of Unknown Metal Has Dimensions 1 cm×1 cm×3 cm1 \mathrm {~cm} ^ { \times } 1 \mathrm {~cm} ^ { \times } 3 \mathrm {~cm}1 cm×1 cm×3 cm

A Block of Unknown Metal Has Dimensions $1 \mathrm {~cm} ^ { \times } 1 \mathrm {~cm} ^ { \times } 3 \mathrm {~cm}$