The amount of time it takes for a pendulum to swing "to-and-fro" through one complete
cycle is called the "period" and is calculated using the following equation: $$T = 2 \pi \sqrt { \frac { I } { m g h } }$$
where
$$\begin{array} { l }
T = \text { period in seconds } \
I = \text { mass moment of inertia } \
m = \text { mass of pendulum in kilograms } \
g = \text { gravitational acceleration, } 9.8 \mathrm {~m} / \mathrm { s } ^ { 2 } \
h = \text { effective length of pendulum in meters }
\end{array}$$
What is the appropriate unit for $I$ if the preceding equation is to be homogeneous in units?

Question

The amount of time it takes for a pendulum to swing "to-and-fro" through one complete
cycle is called the "period" and is calculated using the following equation: $$T = 2 \pi \sqrt { \frac { I } { m g h } }$$
where
$$\begin{array} { l } 
T = \text { period in seconds } \
I = \text { mass moment of inertia } \
m = \text { mass of pendulum in kilograms } \
g = \text { gravitational acceleration, } 9.8 \mathrm {~m} / \mathrm { s } ^ { 2 } \
h = \text { effective length of pendulum in meters }
\end{array}$$
What is the appropriate unit for $I$ if the preceding equation is to be homogeneous in units?

Quizplus · Accepted Answer

The Answer of The amount of time it takes for a pendulum to swing "to-and-fro" through one complete
cycle is called the "period" and is calculated using the following equation: $$T = 2 \pi \sqrt { \frac { I } { m g h } }$$
where
$$\begin{array} { l } 
T = \text { period in seconds } \
I = \text { mass moment of inertia } \
m = \text { mass of pendulum in kilograms } \
g = \text { gravitational acceleration, } 9.8 \mathrm {~m} / \mathrm { s } ^ { 2 } \
h = \text { effective length of pendulum in meters }
\end{array}$$
What is the appropriate unit for $I$ if the preceding equation is to be homogeneous in units?

The Amount of Time It Takes for a Pendulum to Swing