Solve the problem. Give the answer to the nearest tenth.
-The hang-time function $V ( T ) = 48 \mathrm {~T} ^ { 2 }$, relates vertical leap to hang time. A player has a vertical leap of 30 in. What is his hang time?
A) $0.6 \mathrm { sec }$
B) $37.9 \mathrm { sec }$
C) $1.3 \mathrm { sec }$
D) $0.8 \mathrm { sec }$

Question

Quizplus · Accepted Answer

To find the hang time $ T $, use the equation $ V(T) = 48T^2 $. Given $ V = 30 $, solve $ 30 = 48T^2 $. This gives $ T^2 = \frac{30}{48} = 0.625 $. Taking the square root, $ T = \sqrt{0.625} \approx 0.79 $, which rounds to 0.8 seconds.

Solve the Problem V(T)=48 T2V ( T ) = 48 \mathrm {~T} ^ { 2 }V(T)=48 T2

Solve the Problem $V ( T ) = 48 \mathrm {~T} ^ { 2 }$