Solve by completing the square.
-$$x ^ { 2 } = 7 - 8 x$$
A) $- 4 \pm \sqrt { 23 }$
B) $4 + \sqrt { 23 }$
C) $- 4 \pm 2 \sqrt { 23 }$
D) $- 1 \pm \sqrt { 23 }$

Question

Quizplus · Accepted Answer

To solve the equation $x^2 = 7 - 8x$ by completing the square, first move all terms to one side: $x^2 + 8x - 7 = 0$. Then, add $(\frac{8}{2})^2 = 16$ to both sides to complete the square: $x^2 + 8x + 16 = 23$. This gives $(x + 4)^2 = 23$, so $x + 4 = \pm \sqrt{23}$, leading to $x = -4 \pm \sqrt{23}$.

Solve by Completing the Square x2=7−8xx ^ { 2 } = 7 - 8 xx2=7−8x

Solve by Completing the Square $x ^ { 2 } = 7 - 8 x$