Factor completely.
-$49 y ^ { 4 } - 25$
A) $\left( 7 y ^ { 2 } + 5 \right) ^ { 2 }$
B) Prime
C) $\left( 7 y ^ { 2 } + 5 \right) \left( 7 y ^ { 2 } - 5 \right)$
D) $\left( 7 y ^ { 2 } - 5 \right) ^ { 2 }$

Question

Quizplus · Accepted Answer

This is a difference of squares pattern. $49 y ^ { 4 } - 25=(7y^2)^2-5^2=\left( 7 y ^ { 2 } + 5 \right) \left( 7 y ^ { 2 } - 5 \right)$

Factor Completely 49y4−2549 y ^ { 4 } - 2549y4−25 A) (7y2+5)2\left( 7 y ^ { 2 } + 5 \right) ^ { 2 }(7y2+5)2

Factor Completely $49 y ^ { 4 } - 25$ A) $\left( 7 y ^ { 2 } + 5 \right) ^ { 2 }$