Factor.
-$$x ^ { 3 } + 6 x ^ { 2 } - 16 x$$
A) $\left( x ^ { 2 } + 8 \right) ( x - 2 )$
B) $x ( x + 8 ) ( x - 2 )$
C) $x ( x - 8 ) ( x + 2 )$
D) $\left( x ^ { 2 } + 2 \right) ( x - 8 )$

Question

Quizplus · Accepted Answer

First, factor out the greatest common factor, which is $x$, to get $x(x^2 + 6x - 16)$. Then, factor the quadratic $x^2 + 6x - 16$ into $(x + 8)(x - 2)$. Therefore, the fully factored form is $x(x + 8)(x - 2)$.

Factor - x3+6x2−16xx ^ { 3 } + 6 x ^ { 2 } - 16 xx3+6x2−16x

Factor
- $x ^ { 3 } + 6 x ^ { 2 } - 16 x$