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Question 15
Factor by grouping.- 2x3−6x2−6x+182 x ^ { 3 } - 6 x ^ { 2 } - 6 x + 182x3−6x2−6x+18
A) Not possibleB) (x−3) (2x2−6) ( x - 3 ) \left( 2 x ^ { 2 } - 6 \right) (x−3) (2x2−6) C) (x+18) (x2−6x−6) ( x + 18 ) \left( x ^ { 2 } - 6 x - 6 \right) (x+18) (x2−6x−6) D) (x+3) (2x2−6) ( x + 3 ) \left( 2 x ^ { 2 } - 6 \right) (x+3) (2x2−6)
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