Solve the problem.
-How many liters of a $20 \%$ alcohol solution must be mixed with 90 liters of a $80 \%$ solution to get a $40 \%$ solution?
A) $27 \mathrm {~L}$
B) $18 \mathrm {~L}$
C) $180 \mathrm {~L}$
D) $270 \mathrm {~L}$

Question

Quizplus · Accepted Answer

To solve this, we can use the equation representing the total amount of alcohol before and after the mixture: $0.20x + 0.80(90) = 0.40(x + 90)$, where $x$ is the amount of the $20\%$ solution to be added. Solving for $x$ gives $x = 180$ liters.

Solve the Problem 20%20 \%20% Alcohol Solution Must Be Mixed with 90 Liters of A Alcohol

Solve the Problem $20 \%$ Alcohol Solution Must Be Mixed with 90 Liters of A Alcohol