Find the area of the surface. Round your answer to three decimal places.
$$z = \frac { 2 } { 3 } \left( x ^ { 3 / 2 } + y ^ { 3 / 2 } \right) , 0 \leq x \leq 3,0 \leq y \leq 3$$

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The Answer of Find the area of the surface. Round your answer to three decimal places.
$$z = \frac { 2 } { 3 } \left( x ^ { 3 / 2 } + y ^ { 3 / 2 } \right) , 0 \leq x \leq 3,0 \leq y \leq 3$$

Find the Area of the Surface z=23(x3/2+y3/2),0≤x≤3,0≤y≤3z = \frac { 2 } { 3 } \left( x ^ { 3 / 2 } + y ^ { 3 / 2 } \right) , 0 \leq x \leq 3,0 \leq y \leq 3z=32​(x3/2+y3/2),0≤x≤3,0≤y≤3

Find the Area of the Surface $z = \frac { 2 } { 3 } \left( x ^ { 3 / 2 } + y ^ { 3 / 2 } \right) , 0 \leq x \leq 3,0 \leq y \leq 3$