Calculate the double integral. Round your answer to two decimal places.
$$\iint _ { R } \frac { 4 + x ^ { 2 } } { 1 + y ^ { 2 } } d A , R = \{ ( x , y ) \mid 0 \leq x \leq 6,0 \leq y \leq 4 \}$$

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The Answer of Calculate the double integral. Round your answer to two decimal places.
$$\iint _ { R } \frac { 4 + x ^ { 2 } } { 1 + y ^ { 2 } } d A , R = \{ ( x , y ) \mid 0 \leq x \leq 6,0 \leq y \leq 4 \}$$

Calculate the Double Integral ∬R4+x21+y2dA,R={(x,y)∣0≤x≤6,0≤y≤4}\iint _ { R } \frac { 4 + x ^ { 2 } } { 1 + y ^ { 2 } } d A , R = \{ ( x , y ) \mid 0 \leq x \leq 6,0 \leq y \leq 4 \}∬R​1+y24+x2​dA,R={(x,y)∣0≤x≤6,0≤y≤4}

Calculate the Double Integral $\iint _ { R } \frac { 4 + x ^ { 2 } } { 1 + y ^ { 2 } } d A , R = \{ ( x , y ) \mid 0 \leq x \leq 6,0 \leq y \leq 4 \}$