Determine whether the series is convergent or divergent.
$$\sum _ { n = 1 } ^ { \infty } \frac { \tan ^ { - 1 } n } { n \sqrt { n + 6 } }$$

Name: Determine whether the series is convergent or divergent. \[\sum _ { n = 1 } ^ { \infty } \frac { \tan ^ { - 1 } n } { n \sqrt { n + 6 } }\]
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The Answer of Determine whether the series is convergent or divergent.
$$\sum _ { n = 1 } ^ { \infty } \frac { \tan ^ { - 1 } n } { n \sqrt { n + 6 } }$$

Determine Whether the Series Is Convergent or Divergent ∑n=1∞tan⁡−1nnn+6\sum _ { n = 1 } ^ { \infty } \frac { \tan ^ { - 1 } n } { n \sqrt { n + 6 } }n=1∑∞​nn+6​tan−1n​

Determine Whether the Series Is Convergent or Divergent $\sum _ { n = 1 } ^ { \infty } \frac { \tan ^ { - 1 } n } { n \sqrt { n + 6 } }$