Find the point(s) on the curve where the tangent is horizontal.
$$x = t ^ { 3 } - 3 t + 2 , \quad y = t ^ { 3 } - 3 t ^ { 2 } + 2$$

Name: Find the point(s) on the curve where the tangent is horizontal. \[x = t ^ { 3 } - 3 t + 2 , \quad y = t ^ { 3 } - 3 t ^ { 2 } + 2\]
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The Answer of Find the point(s) on the curve where the tangent is horizontal.
$$x = t ^ { 3 } - 3 t + 2 , \quad y = t ^ { 3 } - 3 t ^ { 2 } + 2$$

Find the Point(s) on the Curve Where the Tangent Is x=t3−3t+2,y=t3−3t2+2x = t ^ { 3 } - 3 t + 2 , \quad y = t ^ { 3 } - 3 t ^ { 2 } + 2x=t3−3t+2,y=t3−3t2+2

Find the Point(s) on the Curve Where the Tangent Is $x = t ^ { 3 } - 3 t + 2 , \quad y = t ^ { 3 } - 3 t ^ { 2 } + 2$