Solve the initial-value problem. $x y ^ { t} = y + x ^ { 2 } \sin x , y ( 11 \pi ) = 0$
A) $y = 11 x \sin x$
B) $y = - x \sin x + 11 x$
C) $y = - x \cos x - x$
D) $y = 11 x \cos x - \sin x$
E) $y = x \sin x - 11 x$

Question

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The Answer of Solve the initial-value problem. $x y ^ { t} = y + x ^ { 2 } \sin x , y ( 11 \pi ) = 0$
A) $y = 11 x \sin x$
B) $y = - x \sin x + 11 x$
C) $y = - x \cos x - x$
D) $y = 11 x \cos x - \sin x$
E) $y = x \sin x - 11 x$

Solve the Initial-Value Problem xyt=y+x2sin⁡x,y(11π)=0x y ^ { t} = y + x ^ { 2 } \sin x , y ( 11 \pi ) = 0xyt=y+x2sinx,y(11π)=0

Solve the Initial-Value Problem $x y ^ { t} = y + x ^ { 2 } \sin x , y ( 11 \pi ) = 0$