We modeled populations of aphids and ladybugs with a Lotka-Volterra system. Suppose we modify those equations as follows:
$$\frac { d A } { d t } = 2 A ( 1 - 0.0005 A ) - 0.01 A L$$
$\frac { d L } { d t } = - 0.6 L + 0.0005 A L$
Find the equilibrium solution.
A) $A = 3200 , L = 110$
B) $A = 4700 , L = 90$
C) $A = 3700 , L = 120$
D) $A = 1200 , L = 80$
E) $A = 1500 , L = 100$

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The Answer of We modeled populations of aphids and ladybugs with a Lotka-Volterra system. Suppose we modify those equations as follows:
$$\frac { d A } { d t } = 2 A ( 1 - 0.0005 A ) - 0.01 A L$$
$\frac { d L } { d t } = - 0.6 L + 0.0005 A L$
Find the equilibrium solution.
A) $A = 3200 , L = 110$
B) $A = 4700 , L = 90$
C) $A = 3700 , L = 120$
D) $A = 1200 , L = 80$
E) $A = 1500 , L = 100$

We Modeled Populations of Aphids and Ladybugs with a Lotka-Volterra dAdt=2A(1−0.0005A)−0.01AL\frac { d A } { d t } = 2 A ( 1 - 0.0005 A ) - 0.01 A LdtdA​=2A(1−0.0005A)−0.01AL

We Modeled Populations of Aphids and Ladybugs with a Lotka-Volterra $\frac { d A } { d t } = 2 A ( 1 - 0.0005 A ) - 0.01 A L$