Use long division to evaluate the integral.
$$\int _ { 0 } ^ { 1 } \frac { x ^ { 3 } + 12 x ^ { 2 } - 36 x + 1 } { x ^ { 2 } + 4 x - 12 } d x$$
The choices are rounded to 3 decimal places.

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The Answer of Use long division to evaluate the integral.
$$\int _ { 0 } ^ { 1 } \frac { x ^ { 3 } + 12 x ^ { 2 } - 36 x + 1 } { x ^ { 2 } + 4 x - 12 } d x$$
The choices are rounded to 3 decimal places.

Use Long Division to Evaluate the Integral ∫01x3+12x2−36x+1x2+4x−12dx\int _ { 0 } ^ { 1 } \frac { x ^ { 3 } + 12 x ^ { 2 } - 36 x + 1 } { x ^ { 2 } + 4 x - 12 } d x∫01​x2+4x−12x3+12x2−36x+1​dx

Use Long Division to Evaluate the Integral $\int _ { 0 } ^ { 1 } \frac { x ^ { 3 } + 12 x ^ { 2 } - 36 x + 1 } { x ^ { 2 } + 4 x - 12 } d x$