Find the area of the region bounded by the given curves.
$$y = \sin \left( \frac { \pi x } { 8 } \right) , y = x ^ { 2 } - 8 x$$

Name: Find the area of the region bounded by the given curves. \[y = \sin \left( \frac { \pi x } { 8 } \right) , y = x ^ { 2 } - 8 x\]
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The Answer of Find the area of the region bounded by the given curves.
$$y = \sin \left( \frac { \pi x } { 8 } \right) , y = x ^ { 2 } - 8 x$$

Find the Area of the Region Bounded by the Given y=sin⁡(πx8),y=x2−8xy = \sin \left( \frac { \pi x } { 8 } \right) , y = x ^ { 2 } - 8 xy=sin(8πx​),y=x2−8x

Find the Area of the Region Bounded by the Given $y = \sin \left( \frac { \pi x } { 8 } \right) , y = x ^ { 2 } - 8 x$