Sketch the region bounded by the graphs of the given equations and find the area of that region.
$$y = \sec ^ { 2 } x + 6 , y = 8 , x = - \frac { \pi } { 4 } , x = \frac { \pi } { 4 }$$

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The Answer of Sketch the region bounded by the graphs of the given equations and find the area of that region.
$$y = \sec ^ { 2 } x + 6 , y = 8 , x = - \frac { \pi } { 4 } , x = \frac { \pi } { 4 }$$

Sketch the Region Bounded by the Graphs of the Given y=sec⁡2x+6,y=8,x=−π4,x=π4y = \sec ^ { 2 } x + 6 , y = 8 , x = - \frac { \pi } { 4 } , x = \frac { \pi } { 4 }y=sec2x+6,y=8,x=−4π​,x=4π​

Sketch the Region Bounded by the Graphs of the Given $y = \sec ^ { 2 } x + 6 , y = 8 , x = - \frac { \pi } { 4 } , x = \frac { \pi } { 4 }$