Find the integral using an appropriate trigonometric substitution.
$$\int \frac { x ^ { 3 } } { \sqrt { x ^ { 2 } + 36 } } d x$$

Name: Find the integral using an appropriate trigonometric substitution. \[\int \frac { x ^ { 3 } } { \sqrt { x ^ { 2 } + 36 } } d x\]
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The Answer of Find the integral using an appropriate trigonometric substitution.
$$\int \frac { x ^ { 3 } } { \sqrt { x ^ { 2 } + 36 } } d x$$

Find the Integral Using an Appropriate Trigonometric Substitution ∫x3x2+36dx\int \frac { x ^ { 3 } } { \sqrt { x ^ { 2 } + 36 } } d x∫x2+36​x3​dx

Find the Integral Using an Appropriate Trigonometric Substitution $\int \frac { x ^ { 3 } } { \sqrt { x ^ { 2 } + 36 } } d x$