Find the indefinite integral.
$$\int \frac { \cot ^ { 2 } x } { \cos ^ { 2 } x } d x$$
A) $\cos ^ { 2 } x + C$
B) $\tan x + C$
C) $\csc ^ { 2 } x + C$
D) $- \cot x + C$

Question

Quizplus · Accepted Answer

The integral can be simplified using trigonometric identities: $\cot^2 x = \csc^2 x - 1$ and $\cos^2 x = 1 - \sin^2 x$. The integral becomes $\int (\csc^2 x - 1) \sec^2 x \, dx$, which simplifies to $-\cot x + C$.

Find the Indefinite Integral ∫cot⁡2xcos⁡2xdx\int \frac { \cot ^ { 2 } x } { \cos ^ { 2 } x } d x∫cos2xcot2x​dx

Find the Indefinite Integral $\int \frac { \cot ^ { 2 } x } { \cos ^ { 2 } x } d x$