Find $g ^ { \prime } ( x )$ by evaluating the integral using Part 2 of the Fundamental Theorem and then differentiating.
$$g ( x ) = \int _ { x } ^ { x } ( 6 + \cos t ) d t$$

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The Answer of Find $g ^ { \prime } ( x )$ by evaluating the integral using Part 2 of the Fundamental Theorem and then differentiating.
$$g ( x ) = \int _ { x } ^ { x } ( 6 + \cos t ) d t$$

Find g′(x)g ^ { \prime } ( x )g′(x) By Evaluating the Integral Using Part 2 of the Fundamental

Find $g ^ { \prime } ( x )$ By Evaluating the Integral Using Part 2 of the Fundamental