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For What Values Of cc Does the Curve Have Maximum and Minimum Points for the and Minimum

Question 43

Multiple Choice

For what values of cc does the curve have maximum and minimum points for the given function f(x) =cx45x2+1?f ( x ) = c x ^ { 4 } - 5 x ^ { 2 } + 1 ?
Select the correct answer.


A) For c=0,f(x) =5x2+1c = 0 , f ( x ) = - 5 x ^ { 2 } + 1 , a parabola whose vertex (0,2) ( 0,2 ) , is the absolute maximum.
For c>0,f(x) =cx45x2+1c > 0 , f ( x ) = c x ^ { 4 } - 5 x ^ { 2 } + 1 , opens downward with one minimum points.
For c<0c < 0 , the graph opens upward, and has an absolute maximum at x=0x = 0 and no local minimum.
B) For c=0,f(x) =5x2+1c = 0 , f ( x ) = 5 x ^ { 2 } + 1 , a parabola whose vertex (0,2) ( 0,2 ) , is the absolute maximum.
For c>0,f(x) =cx4+5x2+1c > 0 , f ( x ) = c x ^ { 4 } + 5 x ^ { 2 } + 1 , opens upward with two minimum points.
For c<0c < 0 , the graph opens downward, and has an absolute minimum at x=0x = 0 and no local minimum.
C) For c=0,f(x) =5x2+1c = 0 , f ( x ) = 5 x ^ { 2 } + 1 , a parabola whose vertex (0,3) ( 0,3 ) , is the absolute maximum.
For c>0,f(x) =cx45x2+1c > 0 , f ( x ) = c x ^ { 4 } - 5 x ^ { 2 } + 1 , opens upward with two minimum points.
For c<0c < 0 , the graph opens downward, and has an absolute minimum at x=0x = 0 and no local minimum.
D) For c=0,f(x) =5x2+1c = 0 , f ( x ) = - 5 x ^ { 2 } + 1 , a parabola whose vertex (0,1) ( 0,1 ) , is the absolute maximum.
For c>0,f(x) =cx45x2+1c > 0 , f ( x ) = c x ^ { 4 } - 5 x ^ { 2 } + 1 , opens upward with two minimum points.
For c<0c < 0 , the graph opens downward, and has an absolute maximum at x=0x = 0 and no local minimum.
E) For c=0,f(x) =5x2+1c = 0 , f ( x ) = - 5 x ^ { 2 } + 1 , a parabola whose vertex (0,1) ( 0 , - 1 ) , is the absolute maximum.
For c>0,f(x) =cx4+5x21c > 0 , f ( x ) = c x ^ { 4 } + 5 x ^ { 2 } - 1 , opens downward with two maximum points.
For c<0c < 0 , the graph opens upward, and has an absolute minimum at x=0x = 0 .

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