The altitude of a triangle is increasing at a rate of $1 \mathrm {~cm} / \mathrm { min }$ while the area of the triangle is increasing at a rate of $2 \mathrm {~cm} ^ { 2 } / \mathrm { min }$. At what rate is the base of the triangle changing when the altitude is $10 \mathrm {~cm}$ and the area is $100 \mathrm {~cm} ^ { 2 }$.

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The Answer of The altitude of a triangle is increasing at a rate of $1 \mathrm {~cm} / \mathrm { min }$ while the area of the triangle is increasing at a rate of $2 \mathrm {~cm} ^ { 2 } / \mathrm { min }$. At what rate is the base of the triangle changing when the altitude is $10 \mathrm {~cm}$ and the area is $100 \mathrm {~cm} ^ { 2 }$.

The Altitude of a Triangle Is Increasing at a Rate 1 cm/min1 \mathrm {~cm} / \mathrm { min }1 cm/min

The Altitude of a Triangle Is Increasing at a Rate $1 \mathrm {~cm} / \mathrm { min }$