Use implicit differentiation to find an equation of the tangent line to the curve at the indicated point.
$$y = \sin x y ^ { 6 } ; \quad \left( \frac { \pi } { 2 } , 1 \right)$$

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The Answer of Use implicit differentiation to find an equation of the tangent line to the curve at the indicated point.
$$y = \sin x y ^ { 6 } ; \quad \left( \frac { \pi } { 2 } , 1 \right)$$

Use Implicit Differentiation to Find an Equation of the Tangent y=sin⁡xy6;(π2,1)y = \sin x y ^ { 6 } ; \quad \left( \frac { \pi } { 2 } , 1 \right)y=sinxy6;(2π​,1)

Use Implicit Differentiation to Find an Equation of the Tangent $y = \sin x y ^ { 6 } ; \quad \left( \frac { \pi } { 2 } , 1 \right)$