$$\text { If } f ( x ) = 4 x ^ { 2 } + 2 \text {, find and simplify } \frac { f ( 1 + h ) - f ( 1 ) } { h } \text {, where } h \neq 0$$

Name: \[\text { If } f ( x ) = 4 x ^ { 2 } + 2 \text {, find and simplify } \frac { f ( 1 + h ) - f ( 1 ) } { h } \text {, where } h \neq 0\]
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The Answer of $$\text { If } f ( x ) = 4 x ^ { 2 } + 2 \text {, find and simplify } \frac { f ( 1 + h ) - f ( 1 ) } { h } \text {, where } h \neq 0$$

If f(x)=4x2+2, find and simplify f(1+h)−f(1)h, where h≠0\text { If } f ( x ) = 4 x ^ { 2 } + 2 \text {, find and simplify } \frac { f ( 1 + h ) - f ( 1 ) } { h } \text {, where } h \neq 0 If f(x)=4x2+2, find and simplify hf(1+h)−f(1)​, where h=0

$\text { If } f ( x ) = 4 x ^ { 2 } + 2 \text {, find and simplify } \frac { f ( 1 + h ) - f ( 1 ) } { h } \text {, where } h \neq 0$