The point $P ( 16,4 )$ lies on the curve $y = \sqrt { x }$. If is the point $Q ( x , \sqrt { x } )$, use your calculator to find the slope of the secant line $P Q$ (correct to six decimal places) for the value $x = 3.89$.
A) $m _ { P Q } = - 0.044439$
B) $m _ { P Q } = - 0.167439$
C) $m _ { P Q } = - 0.307439$
D) $m _ { P Q } = 0.377439$
E) $m _ { P Q } = 0.167439$

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The Answer of The point $P ( 16,4 )$ lies on the curve $y = \sqrt { x }$. If is the point $Q ( x , \sqrt { x } )$, use your calculator to find the slope of the secant line $P Q$ (correct to six decimal places) for the value $x = 3.89$.
A) $m _ { P Q } = - 0.044439$
B) $m _ { P Q } = - 0.167439$
C) $m _ { P Q } = - 0.307439$
D) $m _ { P Q } = 0.377439$
E) $m _ { P Q } = 0.167439$

The Point P(16,4)P ( 16,4 )P(16,4) Lies on the Curve y=xy = \sqrt { x }y=x​

The Point $P ( 16,4 )$ Lies on the Curve $y = \sqrt { x }$