Solve for $X$ . Approximate the result to three decimal places. $\log _ { 3 } x = \frac { 1 } { 2 }$
A) $\sqrt { 3 } \approx - 1.732$
B) $\frac { \sqrt { 3 } } { 3 } \approx 1.732$
C) $\sqrt { 3 } \approx 2$
D) $\sqrt { 3 } \approx 1.732$
E) $\sqrt { 3 } = 1.732$

Question

Solve for $X$ . Approximate the result to three decimal places. $\log _ { 3 } x = \frac { 1 } { 2 }$ 
A) $\sqrt { 3 } \approx - 1.732$
B) $\frac { \sqrt { 3 } } { 3 } \approx 1.732$
C) $\sqrt { 3 } \approx 2$
D) $\sqrt { 3 } \approx 1.732$
E) $\sqrt { 3 } = 1.732$

Quizplus · Accepted Answer

Using the definition of logarithms, we have:
$$\log_{3} x = \frac{1}{2} \iff 3^{\frac{1}{2}}=\sqrt{3}=x$$
Approximating $\sqrt{3}$ to three decimal places gives $1.732$, which matches option D).

Solve For XXX Approximate the Result to Three Decimal Places log⁡3x=12\log _ { 3 } x = \frac { 1 } { 2 }log3​x=21​

Solve For $X$ Approximate the Result to Three Decimal Places $\log _ { 3 } x = \frac { 1 } { 2 }$