Which of the given functions is discontinuous?
A)
$f ( x ) = \left\{ \begin{array} { c c }
\frac { 1 } { x - 11 } , & x \neq 11 \
9 , & x = 11
\end{array} \right.$
B)
$f ( x ) = \left\{ \begin{array} { c c }
\frac { 1 } { x - 2 } , & x \geq 11 \
\frac { 1 } { 9 } , & x

Question

Which of the given functions is discontinuous?
A)
$f ( x ) = \left\{ \begin{array} { c c } 
\frac { 1 } { x - 11 } , & x \neq 11 \
9 , & x = 11
\end{array} \right.$
B)
$f ( x ) = \left\{ \begin{array} { c c } 
\frac { 1 } { x - 2 } , & x \geq 11 \
\frac { 1 } { 9 } , & x < 11
\end{array} \right.$

Quizplus · Accepted Answer

Function A is discontinuous at x=11 because the limit does not exist as x approaches 11. On the other hand, function B is continuous everywhere.

Which of the Given Functions Is Discontinuous? A) f(x)={1x−11,x≠119,x=11f ( x ) = \left\{ \begin{array} { c c } \frac { 1 } { x - 11 } , & x \neq 11 \\9 , & x = 11\end{array} \right.f(x)={x−111​,9,​x=11x=11​

Which of the Given Functions Is Discontinuous?
A) $f ( x ) = \left\{ \begin{array} { c c } \frac { 1 } { x - 11 } , & x \neq 11 \\9 , & x = 11\end{array} \right.$