The curve $x = 5 - 10 \cos ^ { 2 } t , y = \tan t \left( 1 - 2 \cos ^ { 2 } t \right)$ cross itself at some point $\left( x _ { 0 } , y _ { 0 } \right)$. Find the equations of both tangent lines at that point.
A) $y = \frac { x } { 5 } , y = - \frac { x } { 10 }$
B)
$y = \frac { x } { 2 } - 10 , y = - \frac { x } { 2 } - 2$
C) $y = x + 5 , y = - x + 5$
D)$y = \frac { x } { 2 } , y = - \frac { x } { 2 }$
E)$y = \frac { x } { 2 } + 8 , y = - \frac { x } { 2 } + 2$

Question

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The Answer of The curve $x = 5 - 10 \cos ^ { 2 } t , y = \tan t \left( 1 - 2 \cos ^ { 2 } t \right)$ cross itself at some point $\left( x _ { 0 } , y _ { 0 } \right)$. Find the equations of both tangent lines at that point.
A) $y = \frac { x } { 5 } , y = - \frac { x } { 10 }$
B)
$y = \frac { x } { 2 } - 10 , y = - \frac { x } { 2 } - 2$
C) $y = x + 5 , y = - x + 5$
D)$y = \frac { x } { 2 } , y = - \frac { x } { 2 }$
E)$y = \frac { x } { 2 } + 8 , y = - \frac { x } { 2 } + 2$

The Curve x=5−10cos⁡2t,y=tan⁡t(1−2cos⁡2t)x = 5 - 10 \cos ^ { 2 } t , y = \tan t \left( 1 - 2 \cos ^ { 2 } t \right)x=5−10cos2t,y=tant(1−2cos2t)

The Curve $x = 5 - 10 \cos ^ { 2 } t , y = \tan t \left( 1 - 2 \cos ^ { 2 } t \right)$