Find the radius of convergence and the interval of convergence of the power series. $$\sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n } ( x - 8 ) ^ { n } } { \sqrt { n } }$$
A) $R = 1 , l = [ 7,9 )$
B) $R = 1 , I = ( 7,9 ]$
C) $R = 8 , l = [ - 8,8 )$
D) $R = 8 , l = ( - 8,8 )$

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The Answer of Find the radius of convergence and the interval of convergence of the power series. $$\sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n } ( x - 8 ) ^ { n } } { \sqrt { n } }$$
A) $R = 1 , l = [ 7,9 )$
B) $R = 1 , I = ( 7,9 ]$
C) $R = 8 , l = [ - 8,8 )$
D) $R = 8 , l = ( - 8,8 )$

Find the Radius of Convergence and the Interval of Convergence ∑n=1∞(−1)n(x−8)nn\sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n } ( x - 8 ) ^ { n } } { \sqrt { n } }n=1∑∞​n​(−1)n(x−8)n​

Find the Radius of Convergence and the Interval of Convergence $\sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n } ( x - 8 ) ^ { n } } { \sqrt { n } }$