Find the indefinite integral.
$$\int \frac { 2 x ^ { 9 } - 6 x ^ { 2 } + 3 } { x ^ { 9 } } d x$$
A) $2 x + \frac { 1 } { x ^ { 6 } } - \frac { 3 } { 8 x ^ { 8 } } + C$
B)
$2 x + \frac { 3 } { 4 x ^ { 8 } } - \frac { 3 } { 10 x ^ { 10 } } + C$
C)
$2 x + x ^ { 6 } - \frac { 3 } { 8 } x ^ { 8 } + C$
D) $2 x + \frac { 3 } { 4 } x ^ { 8 } - \frac { 3 } { 10 } x ^ { 10 } + C$

Question

Quizplus · Accepted Answer

Divide each term in the integrand by $x^9$: $\frac{2x^9}{x^9} - \frac{6x^2}{x^9} + \frac{3}{x^9} = 2 - 6x^{-7} + 3x^{-9}$. Integrating term by term gives $2x - \frac{6}{-6}x^{-6} + \frac{3}{-8}x^{-8} + C = 2x + \frac{1}{x^6} - \frac{3}{8x^8} + C$.

Find the Indefinite Integral ∫2x9−6x2+3x9dx\int \frac { 2 x ^ { 9 } - 6 x ^ { 2 } + 3 } { x ^ { 9 } } d x∫x92x9−6x2+3​dx

Find the Indefinite Integral $\int \frac { 2 x ^ { 9 } - 6 x ^ { 2 } + 3 } { x ^ { 9 } } d x$