The position of an object subjected to constant acceleration can be described by the following function: $x ( t ) = x _ { 0 } + v _ { 0 } t + \frac { 1 } { 2 } a t ^ { 2 }$ where $\begin{array} { l }
x = \text { position } ( \mathrm { m } ) \
x _ { 0 } = \text { initial position } ( \mathrm { m } ) \
v _ { 0 } = \text { initial velocity } ( \mathrm { m } / \mathrm { s } ) \
a = \text { acceleration } \left( \mathrm { m } / \mathrm { s } ^ { \wedge } 2 \right) \
t = \text { time } ( \mathrm { sec } )
\end{array}$ Which type of mathematical model is used here to describe the object's position?
A) Linear model
B) Nonlinear model
C) Exponential model
D) Trigonometric model

Question

The position of an object subjected to constant acceleration can be described by the following function: $x ( t ) = x _ { 0 } + v _ { 0 } t + \frac { 1 } { 2 } a t ^ { 2 }$ where $\begin{array} { l } 
x = \text { position } ( \mathrm { m } ) \
x _ { 0 } = \text { initial position } ( \mathrm { m } ) \
v _ { 0 } = \text { initial velocity } ( \mathrm { m } / \mathrm { s } ) \
a = \text { acceleration } \left( \mathrm { m } / \mathrm { s } ^ { \wedge } 2 \right) \
t = \text { time } ( \mathrm { sec } )
\end{array}$ Which type of mathematical model is used here to describe the object's position?
A) Linear model
B) Nonlinear model
C) Exponential model
D) Trigonometric model

Quizplus · Accepted Answer

The equation $x(t) = x_0 + v_0t + \frac{1}{2}at^2$ is a quadratic equation in terms of time $t$, which makes it a nonlinear model due to the $t^2$ term.

The Position of an Object Subjected to Constant Acceleration Can x(t)=x0+v0t+12at2x ( t ) = x _ { 0 } + v _ { 0 } t + \frac { 1 } { 2 } a t ^ { 2 }x(t)=x0​+v0​t+21​at2

The Position of an Object Subjected to Constant Acceleration Can $x ( t ) = x _ { 0 } + v _ { 0 } t + \frac { 1 } { 2 } a t ^ { 2 }$