Find $\lim _ { x \rightarrow \infty } \frac { 1 - 3 x } { 1 + 7 x }$ (if it exists).
A) 0
B) $- \frac { 3 } { 7 }$
C) $\frac { 3 } { 7 }$
D) $- \infty$
E) limit does not exist

Question

Quizplus · Accepted Answer

We can use the fact that the limit of the ratio of coefficients of highest-degree terms in the numerator and denominator is the limit of the function. Therefore, the limit is $-\frac{3}{7}$, choice (B).

Find lim⁡x→∞1−3x1+7x\lim _ { x \rightarrow \infty } \frac { 1 - 3 x } { 1 + 7 x }limx→∞​1+7x1−3x​

Find $\lim _ { x \rightarrow \infty } \frac { 1 - 3 x } { 1 + 7 x }$