Find the general form of the equation of the plane with the given characteristics. The plane passes through the point $( - 3,6 , - 2 )$ and is parallel to the $y z$-plane
A) $y = 6$
B) $z = - 2$
C) $x + y + z = 1$
D) $y + z = 4$
E) $x = - 3$

Question

Quizplus · Accepted Answer

A plane parallel to the $yz$-plane has a normal vector parallel to the $x$-axis, meaning its equation depends only on $x$. Since it passes through $(-3,6,-2)$, the equation is $x = -3$.

Find the General Form of the Equation of the Plane (−3,6,−2)( - 3,6 , - 2 )(−3,6,−2)

Find the General Form of the Equation of the Plane $( - 3,6 , - 2 )$