Find a System of Linear Equations That Has the Following $$\left( - \frac { 4 } { 7 } , 10 \right)$$

Find a system of linear equations that has the following solution.
$$\left( - \frac { 4 } { 7 } , 10 \right)$$

A) $\left\{ \begin{array} { l } 28 x + 15 y = \frac { 1900 } { 7 } \\ 56 x + 10 y = \frac { 3880 } { 7 } \end{array} \right.$
B) $\left\{ \begin{array} { l } 28 y + 15 x = 134 \\ 56 y + 10 x = 68 \end{array} \right.$
C) $\left\{ \begin{array} { l } 56 x + 10 y = - 166 \\ 28 x + 15 y = - 132 \end{array} \right.$
D) $\left\{ \begin{array} { l } 28 y + 15 x = \frac { 1900 } { 7 } \\ 56 y + 10 x = \frac { 3880 } { 7 } \end{array} \right.$
E) $\left\{ \begin{array} { l } 28 x + 15 y = 134 \\ 56 x + 10 y = 68 \end{array} \right.$